3.5.44 \(\int x (a+b \log (c (d+e \sqrt [3]{x})^n)) \, dx\) [444]

Optimal. Leaf size=136 \[ \frac {b d^5 n \sqrt [3]{x}}{2 e^5}-\frac {b d^4 n x^{2/3}}{4 e^4}+\frac {b d^3 n x}{6 e^3}-\frac {b d^2 n x^{4/3}}{8 e^2}+\frac {b d n x^{5/3}}{10 e}-\frac {1}{12} b n x^2-\frac {b d^6 n \log \left (d+e \sqrt [3]{x}\right )}{2 e^6}+\frac {1}{2} x^2 \left (a+b \log \left (c \left (d+e \sqrt [3]{x}\right )^n\right )\right ) \]

[Out]

1/2*b*d^5*n*x^(1/3)/e^5-1/4*b*d^4*n*x^(2/3)/e^4+1/6*b*d^3*n*x/e^3-1/8*b*d^2*n*x^(4/3)/e^2+1/10*b*d*n*x^(5/3)/e
-1/12*b*n*x^2-1/2*b*d^6*n*ln(d+e*x^(1/3))/e^6+1/2*x^2*(a+b*ln(c*(d+e*x^(1/3))^n))

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Rubi [A]
time = 0.06, antiderivative size = 136, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {2504, 2442, 45} \begin {gather*} \frac {1}{2} x^2 \left (a+b \log \left (c \left (d+e \sqrt [3]{x}\right )^n\right )\right )-\frac {b d^6 n \log \left (d+e \sqrt [3]{x}\right )}{2 e^6}+\frac {b d^5 n \sqrt [3]{x}}{2 e^5}-\frac {b d^4 n x^{2/3}}{4 e^4}+\frac {b d^3 n x}{6 e^3}-\frac {b d^2 n x^{4/3}}{8 e^2}+\frac {b d n x^{5/3}}{10 e}-\frac {1}{12} b n x^2 \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x*(a + b*Log[c*(d + e*x^(1/3))^n]),x]

[Out]

(b*d^5*n*x^(1/3))/(2*e^5) - (b*d^4*n*x^(2/3))/(4*e^4) + (b*d^3*n*x)/(6*e^3) - (b*d^2*n*x^(4/3))/(8*e^2) + (b*d
*n*x^(5/3))/(10*e) - (b*n*x^2)/12 - (b*d^6*n*Log[d + e*x^(1/3)])/(2*e^6) + (x^2*(a + b*Log[c*(d + e*x^(1/3))^n
]))/2

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 2442

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[(f + g*
x)^(q + 1)*((a + b*Log[c*(d + e*x)^n])/(g*(q + 1))), x] - Dist[b*e*(n/(g*(q + 1))), Int[(f + g*x)^(q + 1)/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*f - d*g, 0] && NeQ[q, -1]

Rule 2504

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[I
nt[x^(Simplify[(m + 1)/n] - 1)*(a + b*Log[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p,
q}, x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) &&  !(EqQ[q, 1] && ILtQ[n, 0] &&
IGtQ[m, 0])

Rubi steps

\begin {align*} \int x \left (a+b \log \left (c \left (d+e \sqrt [3]{x}\right )^n\right )\right ) \, dx &=3 \text {Subst}\left (\int x^5 \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx,x,\sqrt [3]{x}\right )\\ &=\frac {1}{2} x^2 \left (a+b \log \left (c \left (d+e \sqrt [3]{x}\right )^n\right )\right )-\frac {1}{2} (b e n) \text {Subst}\left (\int \frac {x^6}{d+e x} \, dx,x,\sqrt [3]{x}\right )\\ &=\frac {1}{2} x^2 \left (a+b \log \left (c \left (d+e \sqrt [3]{x}\right )^n\right )\right )-\frac {1}{2} (b e n) \text {Subst}\left (\int \left (-\frac {d^5}{e^6}+\frac {d^4 x}{e^5}-\frac {d^3 x^2}{e^4}+\frac {d^2 x^3}{e^3}-\frac {d x^4}{e^2}+\frac {x^5}{e}+\frac {d^6}{e^6 (d+e x)}\right ) \, dx,x,\sqrt [3]{x}\right )\\ &=\frac {b d^5 n \sqrt [3]{x}}{2 e^5}-\frac {b d^4 n x^{2/3}}{4 e^4}+\frac {b d^3 n x}{6 e^3}-\frac {b d^2 n x^{4/3}}{8 e^2}+\frac {b d n x^{5/3}}{10 e}-\frac {1}{12} b n x^2-\frac {b d^6 n \log \left (d+e \sqrt [3]{x}\right )}{2 e^6}+\frac {1}{2} x^2 \left (a+b \log \left (c \left (d+e \sqrt [3]{x}\right )^n\right )\right )\\ \end {align*}

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Mathematica [A]
time = 0.07, size = 133, normalized size = 0.98 \begin {gather*} \frac {a x^2}{2}-\frac {1}{2} b e n \left (-\frac {d^5 \sqrt [3]{x}}{e^6}+\frac {d^4 x^{2/3}}{2 e^5}-\frac {d^3 x}{3 e^4}+\frac {d^2 x^{4/3}}{4 e^3}-\frac {d x^{5/3}}{5 e^2}+\frac {x^2}{6 e}+\frac {d^6 \log \left (d+e \sqrt [3]{x}\right )}{e^7}\right )+\frac {1}{2} b x^2 \log \left (c \left (d+e \sqrt [3]{x}\right )^n\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x*(a + b*Log[c*(d + e*x^(1/3))^n]),x]

[Out]

(a*x^2)/2 - (b*e*n*(-((d^5*x^(1/3))/e^6) + (d^4*x^(2/3))/(2*e^5) - (d^3*x)/(3*e^4) + (d^2*x^(4/3))/(4*e^3) - (
d*x^(5/3))/(5*e^2) + x^2/(6*e) + (d^6*Log[d + e*x^(1/3)])/e^7))/2 + (b*x^2*Log[c*(d + e*x^(1/3))^n])/2

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int x \left (a +b \ln \left (c \left (d +e \,x^{\frac {1}{3}}\right )^{n}\right )\right )\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a+b*ln(c*(d+e*x^(1/3))^n)),x)

[Out]

int(x*(a+b*ln(c*(d+e*x^(1/3))^n)),x)

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Maxima [A]
time = 0.29, size = 104, normalized size = 0.76 \begin {gather*} -\frac {1}{120} \, {\left (60 \, d^{6} e^{\left (-7\right )} \log \left (x^{\frac {1}{3}} e + d\right ) + {\left (30 \, d^{4} x^{\frac {2}{3}} e - 60 \, d^{5} x^{\frac {1}{3}} - 20 \, d^{3} x e^{2} + 15 \, d^{2} x^{\frac {4}{3}} e^{3} - 12 \, d x^{\frac {5}{3}} e^{4} + 10 \, x^{2} e^{5}\right )} e^{\left (-6\right )}\right )} b n e + \frac {1}{2} \, b x^{2} \log \left ({\left (x^{\frac {1}{3}} e + d\right )}^{n} c\right ) + \frac {1}{2} \, a x^{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*log(c*(d+e*x^(1/3))^n)),x, algorithm="maxima")

[Out]

-1/120*(60*d^6*e^(-7)*log(x^(1/3)*e + d) + (30*d^4*x^(2/3)*e - 60*d^5*x^(1/3) - 20*d^3*x*e^2 + 15*d^2*x^(4/3)*
e^3 - 12*d*x^(5/3)*e^4 + 10*x^2*e^5)*e^(-6))*b*n*e + 1/2*b*x^2*log((x^(1/3)*e + d)^n*c) + 1/2*a*x^2

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Fricas [A]
time = 0.40, size = 114, normalized size = 0.84 \begin {gather*} \frac {1}{120} \, {\left (20 \, b d^{3} n x e^{3} + 60 \, b x^{2} e^{6} \log \left (c\right ) - 10 \, {\left (b n - 6 \, a\right )} x^{2} e^{6} - 60 \, {\left (b d^{6} n - b n x^{2} e^{6}\right )} \log \left (x^{\frac {1}{3}} e + d\right ) - 6 \, {\left (5 \, b d^{4} n e^{2} - 2 \, b d n x e^{5}\right )} x^{\frac {2}{3}} + 15 \, {\left (4 \, b d^{5} n e - b d^{2} n x e^{4}\right )} x^{\frac {1}{3}}\right )} e^{\left (-6\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*log(c*(d+e*x^(1/3))^n)),x, algorithm="fricas")

[Out]

1/120*(20*b*d^3*n*x*e^3 + 60*b*x^2*e^6*log(c) - 10*(b*n - 6*a)*x^2*e^6 - 60*(b*d^6*n - b*n*x^2*e^6)*log(x^(1/3
)*e + d) - 6*(5*b*d^4*n*e^2 - 2*b*d*n*x*e^5)*x^(2/3) + 15*(4*b*d^5*n*e - b*d^2*n*x*e^4)*x^(1/3))*e^(-6)

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Sympy [A]
time = 2.70, size = 131, normalized size = 0.96 \begin {gather*} \frac {a x^{2}}{2} + b \left (- \frac {e n \left (\frac {3 d^{6} \left (\begin {cases} \frac {\sqrt [3]{x}}{d} & \text {for}\: e = 0 \\\frac {\log {\left (d + e \sqrt [3]{x} \right )}}{e} & \text {otherwise} \end {cases}\right )}{e^{6}} - \frac {3 d^{5} \sqrt [3]{x}}{e^{6}} + \frac {3 d^{4} x^{\frac {2}{3}}}{2 e^{5}} - \frac {d^{3} x}{e^{4}} + \frac {3 d^{2} x^{\frac {4}{3}}}{4 e^{3}} - \frac {3 d x^{\frac {5}{3}}}{5 e^{2}} + \frac {x^{2}}{2 e}\right )}{6} + \frac {x^{2} \log {\left (c \left (d + e \sqrt [3]{x}\right )^{n} \right )}}{2}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*ln(c*(d+e*x**(1/3))**n)),x)

[Out]

a*x**2/2 + b*(-e*n*(3*d**6*Piecewise((x**(1/3)/d, Eq(e, 0)), (log(d + e*x**(1/3))/e, True))/e**6 - 3*d**5*x**(
1/3)/e**6 + 3*d**4*x**(2/3)/(2*e**5) - d**3*x/e**4 + 3*d**2*x**(4/3)/(4*e**3) - 3*d*x**(5/3)/(5*e**2) + x**2/(
2*e))/6 + x**2*log(c*(d + e*x**(1/3))**n)/2)

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 271 vs. \(2 (104) = 208\).
time = 4.37, size = 271, normalized size = 1.99 \begin {gather*} \frac {1}{120} \, {\left (60 \, b x^{2} e \log \left (c\right ) + 60 \, a x^{2} e + {\left (60 \, {\left (x^{\frac {1}{3}} e + d\right )}^{6} e^{\left (-5\right )} \log \left (x^{\frac {1}{3}} e + d\right ) - 360 \, {\left (x^{\frac {1}{3}} e + d\right )}^{5} d e^{\left (-5\right )} \log \left (x^{\frac {1}{3}} e + d\right ) + 900 \, {\left (x^{\frac {1}{3}} e + d\right )}^{4} d^{2} e^{\left (-5\right )} \log \left (x^{\frac {1}{3}} e + d\right ) - 1200 \, {\left (x^{\frac {1}{3}} e + d\right )}^{3} d^{3} e^{\left (-5\right )} \log \left (x^{\frac {1}{3}} e + d\right ) + 900 \, {\left (x^{\frac {1}{3}} e + d\right )}^{2} d^{4} e^{\left (-5\right )} \log \left (x^{\frac {1}{3}} e + d\right ) - 360 \, {\left (x^{\frac {1}{3}} e + d\right )} d^{5} e^{\left (-5\right )} \log \left (x^{\frac {1}{3}} e + d\right ) - 10 \, {\left (x^{\frac {1}{3}} e + d\right )}^{6} e^{\left (-5\right )} + 72 \, {\left (x^{\frac {1}{3}} e + d\right )}^{5} d e^{\left (-5\right )} - 225 \, {\left (x^{\frac {1}{3}} e + d\right )}^{4} d^{2} e^{\left (-5\right )} + 400 \, {\left (x^{\frac {1}{3}} e + d\right )}^{3} d^{3} e^{\left (-5\right )} - 450 \, {\left (x^{\frac {1}{3}} e + d\right )}^{2} d^{4} e^{\left (-5\right )} + 360 \, {\left (x^{\frac {1}{3}} e + d\right )} d^{5} e^{\left (-5\right )}\right )} b n\right )} e^{\left (-1\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*log(c*(d+e*x^(1/3))^n)),x, algorithm="giac")

[Out]

1/120*(60*b*x^2*e*log(c) + 60*a*x^2*e + (60*(x^(1/3)*e + d)^6*e^(-5)*log(x^(1/3)*e + d) - 360*(x^(1/3)*e + d)^
5*d*e^(-5)*log(x^(1/3)*e + d) + 900*(x^(1/3)*e + d)^4*d^2*e^(-5)*log(x^(1/3)*e + d) - 1200*(x^(1/3)*e + d)^3*d
^3*e^(-5)*log(x^(1/3)*e + d) + 900*(x^(1/3)*e + d)^2*d^4*e^(-5)*log(x^(1/3)*e + d) - 360*(x^(1/3)*e + d)*d^5*e
^(-5)*log(x^(1/3)*e + d) - 10*(x^(1/3)*e + d)^6*e^(-5) + 72*(x^(1/3)*e + d)^5*d*e^(-5) - 225*(x^(1/3)*e + d)^4
*d^2*e^(-5) + 400*(x^(1/3)*e + d)^3*d^3*e^(-5) - 450*(x^(1/3)*e + d)^2*d^4*e^(-5) + 360*(x^(1/3)*e + d)*d^5*e^
(-5))*b*n)*e^(-1)

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Mupad [B]
time = 0.42, size = 111, normalized size = 0.82 \begin {gather*} \frac {a\,x^2}{2}-\frac {b\,n\,x^2}{12}+\frac {b\,x^2\,\ln \left (c\,{\left (d+e\,x^{1/3}\right )}^n\right )}{2}+\frac {b\,d^3\,n\,x}{6\,e^3}+\frac {b\,d\,n\,x^{5/3}}{10\,e}-\frac {b\,d^6\,n\,\ln \left (d+e\,x^{1/3}\right )}{2\,e^6}-\frac {b\,d^2\,n\,x^{4/3}}{8\,e^2}-\frac {b\,d^4\,n\,x^{2/3}}{4\,e^4}+\frac {b\,d^5\,n\,x^{1/3}}{2\,e^5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a + b*log(c*(d + e*x^(1/3))^n)),x)

[Out]

(a*x^2)/2 - (b*n*x^2)/12 + (b*x^2*log(c*(d + e*x^(1/3))^n))/2 + (b*d^3*n*x)/(6*e^3) + (b*d*n*x^(5/3))/(10*e) -
(b*d^6*n*log(d + e*x^(1/3)))/(2*e^6) - (b*d^2*n*x^(4/3))/(8*e^2) - (b*d^4*n*x^(2/3))/(4*e^4) + (b*d^5*n*x^(1/
3))/(2*e^5)

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